A 0.944 M solution of glucose, C₆H₁₂O₆, in water has a density of 1.0624 g/mL at 20 °C. What is the concentration of this solution in the following units? (b) Mass percent

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1. First, understand that mass percent is defined as the mass of the solute divided by the total mass of the solution, multiplied by 100%. We need to find the mass of glucose and the total mass of the solution.
2. Calculate the mass of glucose in 1 liter of solution. Since the molarity is 0.944 M, this means there are 0.944 moles of glucose in 1 liter of solution. Use the molar mass of glucose (C6H12O6), which is approximately 180.18 g/mol, to find the mass of glucose: mass of glucose = 0.944 moles * 180.18 g/mol.
3. Next, calculate the total mass of the solution. Use the density of the solution, which is 1.0624 g/mL. Since 1 liter is 1000 mL, the total mass of the solution is: total mass of solution = 1.0624 g/mL * 1000 mL.
4. Now, calculate the mass percent of glucose in the solution using the formula: mass percent = (mass of glucose / total mass of solution) * 100%.
5. Finally, substitute the values obtained from the previous steps into the mass percent formula to find the concentration of the solution in mass percent.