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Ch.1 - Chemical Tools: Experimentation & Measurement

Ch.2 - Atoms, Molecules & Ions

Ch.3 - Mass Relationships in Chemical Reactions

BONUS: Lab Techniques and Procedures

BONUS: Mathematical Operations and Functions

Ch.4 - Reactions in Aqueous Solution

Ch.5 - Periodicity & Electronic Structure of Atoms

Ch.6 - Ionic Compounds: Periodic Trends and Bonding Theory

Ch.7 - Covalent Bonding and Electron-Dot Structures

Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure

Ch.9 - Thermochemistry: Chemical Energy

Ch.10 - Gases: Their Properties & Behavior

Ch.11 - Liquids & Phase Changes

Ch.12 - Solids and Solid-State Materials

Ch.13 - Solutions & Their Properties

Ch.14 - Chemical Kinetics

Ch.15 - Chemical Equilibrium

Ch.16 - Aqueous Equilibria: Acids & Bases

Ch.17 - Applications of Aqueous Equilibria

Ch.18 - Thermodynamics: Entropy, Free Energy & Equilibrium

Ch.19 - Electrochemistry

Ch.20 - Nuclear Chemistry

Ch.21 - Transition Elements and Coordination Chemistry

Ch.22 - The Main Group Elements

Ch.23 - Organic and Biological Chemistry

Equilibrium Constant Calculations

Given the following data at 1500 K:Fe2O3(s) ⇌ 2 Fe(l) + 3/2 O2(g); K1 = 5.0

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Chapter 15, Problem 15.64

Calculate the value of the equilibrium constant at 427 °C for the reaction
Na O1s2 + 1>2 O 1g2 ∆ Na O 1s2
given the following equilibrium constants at 427 °C.
Na2O1s2 ∆ 2 Na1l2 + 1>2 O21g2 Kc = 2 * 10-25 Na O 1s2 ∆ 2 Na1l2 + O 1g2 K = 5 * 10-29

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Chapter 15, Problem 15.64

Calculate the value of the equilibrium constant at 427 °C for the reactionNa O1s2 + 1>2 O 1g2 ∆ Na O 1s2given the following equilibrium constants at 427 °C.Na2O1s2 ∆ 2 Na1l2 + 1>2 O21g2 Kc = 2 * 10-25 Na O 1s2 ∆ 2 Na1l2 + O 1g2 K = 5 * 10-29

Calculate the value of the equilibrium constant at 427 °C for the reaction
Na O1s2 + 1>2 O 1g2 ∆ Na O 1s2
given the following equilibrium constants at 427 °C.
Na2O1s2 ∆ 2 Na1l2 + 1>2 O21g2 Kc = 2 * 10-25 Na O 1s2 ∆ 2 Na1l2 + O 1g2 K = 5 * 10-29