Here it says determine the systematic name of the following alkene. So to name this alkene, we're going to follow the given steps here it says find the longest carbon chain which represents our parent chain and assign a name according to the prefix and the modifier. The parent chain should include a double bond and have greater number of carbons. Now if it's cyclic, we add the prefix of cyclo to the name of the alkene chain. If a tie between longest chains choose chain with more substituents.

So if we take a look here, what's our longest chain? Our longest chain appears to be this here. This carbon up here which is a methyl is our substituent. So Step 2 says assign name to all substituents. So this would be methyl start numbering the chain from the end closest to the double bond. So the double bond is here on the left. So we start numbering on this side 1, 2, 3, 4, 5 and 6. Assign location to the first double bonded carbon if double bonded in a ring. Note location is not necessary repeat from previous naming topics.

So go back and take a look at my videos on naming out canes with substituents because it talks about how we give the numerical location for each of the substituents, how we name them alphabetically. And here we have step 7 where we add CIS or trans designation to the front of the name if applicable. Alright, so first let's just name this before we worry about Sis and trains. We're going to say here our substituent is methylants on carbon #4, so it'd be 4 methyl. We then have to talk about the first double bonded carbon. The double bond starts on carbon #2, so we'd say the location is 2.

It's a six carbon chain, which is hexane as an alkane, but here it's an alkene, so we change the ane ending to ENE. So this would be two hexene. Now we said that if we have two groups attached to our π bond then we use CIS and trans. So here is a group attached to our double bonded carbon which contains the π bond, and here is another group attached. So we do have two groups attached to our Pi bonds in terms of those two alkene carbons. Remember we create a border here between the double bonded carbons and we can see that the two groups that I basically put in within those blue boxes, they're on different sides of this border.

Because they're on different sides of this border, that means that they are trans to one another. So we put trans at the beginning of the name. So the name of this particular alkene would be trans 4, methyl 2, hexane.