Multiple ChoiceWrite the given quadratic equation in standard form. Identify a, b, and c. −4x2+x=8-4x^2+x=8−4x2+x=8267views5rank
Multiple ChoiceSolve the given quadratic equation by factoring. 3x2+12x=03x^2+12x=03x2+12x=0220views4rank2comments
Textbook QuestionMatch the equation in Column I with its solution(s) in Column II. x^2 - 5 = 0172views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Which equation is set up for direct use of the zero-factor property? Solve it241views
Textbook QuestionAnswer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. Find two consecutive integers whose product is 110.469views1rank
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. Find two consecutive even integers whose product is 168.176views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Only one of the equations does not require Step 1 of the method for completing the square described in this section. Which one is it? Solve it.183views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Only one of the equations is set up so that the values of a, b, and c can be determined immediately. Which one is it? Solve it.167views
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. The sum of the squares of two consecutive odd integers is 202. Find the integers194views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 3x^2 = 27333views
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. The sum of the squares of two consecutive even integers is 52. Find the integers.187views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 5x^2 = 45293views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 2x^2 - x = 15210views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. -6x^2 + 7x = -10218views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 3x^2 - 1 = 47403views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 2x^2 - 5 = - 55211views
Textbook QuestionSolve each problem. See Examples 1 and 2. Dimensions of a Square. The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in.2. Find the lengths of the sides of the two squares.375views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 9x^2 - 12x + 4 = 0288views
Textbook QuestionSolve each problem. See Examples 1. Dimensions of a Parking Lot. A parking lot has a rectangular area of 40,000 yd2. The length is 200 yd more than twice the width. Find the dimensions of the lot.202views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 36x^2 + 60x + 25 = 0162views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (x - 3)^2 = - 5292views
Textbook QuestionSolve each equation using the square root property. See Example 2. 48 - x^2 = 0277views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (3x + 2)^2 = 9170views
Textbook QuestionManufacturing to Specifications. A manufacturing firm wants to package its product in a cylindrical container 3 ft high with surface area 8π ft2. What should the radius of the circular top and bottom of the container be? (Hint: The surface area consists of the circular top and bottom and a rectangle that represents the side cut open vertically and unrolled.)196views
Textbook QuestionSolve each equation using the square root property. See Example 2. x^2 = -400252views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (4x - 1)^2 = 16203views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (8x - 3)^2 = 5191views
Textbook QuestionRadius of a CanA can of Blue Runner Red Kidney Beans has surface area 371 cm^2. Its height is 12 cm. What is the radius of the circular top? Round to the nearest hun-dredth.253views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. x^2 - 7x + 12 = 0163views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 + 3x438views
Textbook QuestionSolve each problem. See Example 2. Length of a WalkwayA nature conservancy group decides to construct a raised wooden walkway through a wetland area. To enclose the most interesting part of the wetlands, the walkway will have the shape of a right triangle with one leg 700 yd longer than the other and the hypotenuse 100 yd longer than the longer leg. Find the total length of the walkway.247views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - 7x320views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. x^2 - 2x - 2 = 0395views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. 2x^2 + x = 10220views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - (2/3)x335views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - (1/3)x335views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. -3x^2 + 6x + 5 = 0187views
Textbook QuestionWhich equation has two real, distinct solutions? Do not actually solve. A. (3x-4)² = -9 B. (4-7x)² = 0 C. (5x-9)(5x-9) = 0 D. (7x+4)² = 11205views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. 3x^2 - 9x + 7 = 0342views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 - x - 1 = 0205views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 - 6x - 11 = 0227views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number and type of solutions. 16x² +3 = -26x144views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 + 4x + 1 = 0258views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 - 6x = -7211views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 = 2x - 5186views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 - 5x + 6 = 0206views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 + 3x - 1 = 0184views
Textbook QuestionSolve each problem. Dimensions of a Right TriangleThe shortest side of a right triangle is 7 in. shorter than the middle side, while the longest side (the hypot-enuse) is 1 in. longer than the middle side. Find the lengths of the sides.153views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. 2/3x^2 + 1/4x = 3250views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. (4x - 1)(x + 2) = 4x315views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. 3x^2 - 5x - 10 = 0317views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. x^2 + 8x + 15 = 0231views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. x^2 + 5x + 3 = 0650views
Textbook QuestionSolve each cubic equation using factoring and the quadratic formula. See Example 7. x^3 - 27 = 0463views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. 3x^2 - 3x - 4 = 0269views
Textbook QuestionSolve each cubic equation using factoring and the quadratic formula. See Example 7. x^3 + 64 = 0278views
Textbook QuestionSolve each equation in Exercises 68–70 using the quadratic formula. 2x^2 = 3-4x282views
Textbook QuestionIn Exercises 71–72, without solving the given quadratic equation, determine the number and type of solutions. 9x^2 = 2-3x331views
Textbook QuestionSolve each equation in Exercises 73–81 by the method of your choice. 3x^2-7x+1 =0206views
Textbook QuestionSolve each equation for the specified variable. (Assume no denominators are 0.) See Example 8. r = r_0+(1/2)at^2, for t188views
Textbook QuestionSolve each equation in Exercises 73–81 by the method of your choice. (x-3)^2 - 25 = 0263views
Textbook QuestionSolve each equation for the specified variable. (Assume no denominators are 0.) See Example 8. h = -16t^2+v_0t+s_0, for t177views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. 2x^2 - 11x + 3 = 0237views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. x^2 - 2x + 1 = 0215views
Textbook QuestionFor each equation, (b) solve for y in terms of x. See Example 8. 4x^2 - 2xy + 3y^2 = 2319views
Textbook QuestionFor each equation, (a) solve for x in terms of y. See Example 8. 2x^2 + 4xy - 3y^2 = 2167views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. x^2 - 3x - 7 = 0318views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 2x^2 - x = 1237views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 3x^2 + 5x + 2 = 0186views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 4x^2 = -6x + 3315views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 8x^2 - 72 = 0237views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (2x + 3)(x + 4) = 1281views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (2x - 5)(x + 1) = 2199views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (3x - 4)^2 = 16190views
Textbook QuestionAnswer each question. Find the values of a, b, and c for which the quadratic equation. ax^2 + bx + c = 0 has the given numbers as solutions. (Hint: Use the zero-factor property in reverse.) 4, 5394views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 3x^2 - 12x + 12 = 0252views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. x^2 - 4x + 29 = 0204views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. x^2 = 4x - 7202views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 2x^2 - 7x = 0191views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 1/x + 1/(x + 2) = 1/3226views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = x^2 - 4x - 5209views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = - (x + 1)^2 + 4325views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y = 2x^2 - 3x and y = 2314views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y = 5x^2 + 3x and y = 2228views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y1 = 2x^2 + 5x - 4, y2 = - x^2 + 15x - 10, and y1 - y2 = 0325views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y1 = - x^2 + 4x - 2, y2 = - 3x^2 + x - 1, and y1 - y2 = 0302views
Textbook QuestionWhen the sum of 6 and twice a positive number is subtracted from the square of the number, 0 results. Find the number.247views
Textbook QuestionWhen the sum of 1 and twice a negative number is subtracted from twice the square of the number, 0 results. Find the number.214views