for-the-general-term-of-the-sequence-given-write-its-first-four-terms-an2n13n2an

Question

For the general term of the sequence given, write its first four terms: $a_{n}=\frac{\left(2n+1\right)!}{3n^2}$

Accepted Answer

2, 10, $a_{n}=\frac{\left(2n+1\right)!}{3n^2}$ , 7560

Answer

2, 10, 560, 7560

Answer

10, 50, $a_{n}=\frac{\left(2n+1\right)!}{3n^2}$ , 7560

Answer

2, 10, $a_{n}=\frac{\left(2n+1\right)!}{3n^2}$ , 6570

For the general term of the sequence given, write its first four terms: ﻿an=(2n+1)!3n2a_{n}=\frac{\left(2n+1\right)!}{3n^2}an​=3n2(2n+1)!​﻿