Skip to main content
Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
Chapter 6, Problem 23

Write the partial fraction decomposition of each rational expression. (x2-6x+3)/(x − 2)3

Verified step by step guidance
1
Identify the form of the denominator. Here, the denominator is \( (x - 2)^3 \), which is a repeated linear factor raised to the third power.
Set up the partial fraction decomposition with terms for each power of the repeated factor. Since the denominator is \( (x - 2)^3 \), the decomposition will have three terms: \( \frac{A}{x - 2} + \frac{B}{(x - 2)^2} + \frac{C}{(x - 2)^3} \), where \(A\), \(B\), and \(C\) are constants to be determined.
Write the equation equating the original rational expression to the sum of the partial fractions: \[ \frac{x^2 - 6x + 3}{(x - 2)^3} = \frac{A}{x - 2} + \frac{B}{(x - 2)^2} + \frac{C}{(x - 2)^3} \]
Multiply both sides of the equation by \( (x - 2)^3 \) to clear the denominators, resulting in: \[ x^2 - 6x + 3 = A(x - 2)^2 + B(x - 2) + C \]
Expand the right side and then equate the coefficients of corresponding powers of \(x\) on both sides to form a system of equations. Solve this system to find the values of \(A\), \(B\), and \(C\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
8m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Rational Expressions

A rational expression is a fraction where both the numerator and denominator are polynomials. Understanding how to manipulate these expressions, including factoring and simplifying, is essential before performing partial fraction decomposition.
Recommended video:
Guided course
02:58
Rationalizing Denominators

Partial Fraction Decomposition

Partial fraction decomposition breaks a complex rational expression into a sum of simpler fractions with denominators that are factors of the original denominator. This technique is useful for integration and solving equations involving rational expressions.
Recommended video:
4:07
Decomposition of Functions

Repeated Linear Factors in Denominators

When the denominator has repeated linear factors, such as (x − 2)³, the decomposition includes terms with increasing powers of that factor in the denominator. Each power from 1 up to the highest exponent must be included as separate terms in the decomposition.
Recommended video:
Guided course
02:58
Rationalizing Denominators