In Exercises 9 - 16, find the following matrices: d. - 3A + 2B 4 1 5 9 A = B = 3 2 0 7

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1. Identify the matrices A and B: A = \begin{bmatrix} 4 & 1 \\ 3 & 2 \end{bmatrix}, B = \begin{bmatrix} 5 & 9 \\ 0 & 7 \end{bmatrix}.
2. Calculate -3A by multiplying each element of matrix A by -3: -3A = \begin{bmatrix} -3 \times 4 & -3 \times 1 \\ -3 \times 3 & -3 \times 2 \end{bmatrix}.
3. Calculate 2B by multiplying each element of matrix B by 2: 2B = \begin{bmatrix} 2 \times 5 & 2 \times 9 \\ 2 \times 0 & 2 \times 7 \end{bmatrix}.
4. Add the resulting matrices from -3A and 2B: -3A + 2B = \begin{bmatrix} (-3 \times 4) + (2 \times 5) & (-3 \times 1) + (2 \times 9) \\ (-3 \times 3) + (2 \times 0) & (-3 \times 2) + (2 \times 7) \end{bmatrix}.
5. Simplify each element in the resulting matrix to find the final matrix.