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Ch. 3 - Polynomial and Rational Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
Chapter 4, Problem 20

Write an equation that expresses each relationship. Then solve the equation for y. x varies directly as z and inversely as the sum of y and w.

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Identify the type of variation described: "x varies directly as z" means x is proportional to z, so we can write \(x = k \cdot z\) for some constant \(k\).
The phrase "and inversely as the sum of y and w" means x is inversely proportional to \((y + w)\), so we include this in the equation as \(x = \frac{k \cdot z}{y + w}\).
Write the full equation expressing the relationship: \(x = \frac{k \cdot z}{y + w}\), where \(k\) is the constant of proportionality.
To solve for \(y\), start by multiplying both sides of the equation by \((y + w)\) to eliminate the denominator: \(x(y + w) = k \cdot z\).
Next, divide both sides by \(x\) to isolate \((y + w)\): \(y + w = \frac{k \cdot z}{x}\). Finally, subtract \(w\) from both sides to solve for \(y\): \(y = \frac{k \cdot z}{x} - w\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Direct Variation

Direct variation describes a relationship where one variable is proportional to another. If x varies directly as z, it means x = k * z for some constant k. This implies that as z increases, x increases proportionally, and vice versa.
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Inverse Variation

Inverse variation means one variable changes in the opposite way to another. If x varies inversely as a quantity, then x = k / (that quantity). Here, as the denominator increases, x decreases, showing an inverse proportionality.
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Forming and Solving Equations for a Variable

To solve for y, first write the equation expressing the given variation relationships. Then, isolate y by algebraic manipulation, such as multiplying both sides, combining like terms, and using inverse operations to express y explicitly.
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