Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
2:54 minutes
Problem 25b
Textbook Question
Textbook QuestionA rectangular soccer field is twice as long as it is wide. If the perimeter of the soccer field is 300 yards, what are its dimensions?
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Perimeter of a Rectangle
The perimeter of a rectangle is the total distance around the shape, calculated by the formula P = 2L + 2W, where L is the length and W is the width. Understanding this formula is essential for solving problems related to the dimensions of rectangular shapes, as it allows us to relate the length and width to a given perimeter.
Relationship Between Length and Width
In this problem, it is stated that the length of the soccer field is twice its width. This relationship can be expressed mathematically as L = 2W. Recognizing and using this relationship is crucial for substituting variables and simplifying the equations needed to find the dimensions of the field.
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Solving Linear Equations
Solving linear equations involves finding the value of variables that satisfy the equation. In this context, once the perimeter equation and the relationship between length and width are established, we can substitute and solve for W (width) and then find L (length). Mastery of this concept is vital for determining the dimensions of the soccer field.
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