Write an equation for the inverse function of each one-to-one function given. ƒ(x) = 4x+2
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Start with the given function: \(f(x) = 4^{x} + 2\).
To find the inverse function, first replace \(f(x)\) with \(y\): \(y = 4^{x} + 2\).
Swap the variables \(x\) and \(y\) to reflect the inverse relationship: \(x = 4^{y} + 2\).
Isolate the exponential term by subtracting 2 from both sides: \(x - 2 = 4^{y}\).
Take the logarithm base 4 of both sides to solve for \(y\): \(y = \log_{4}(x - 2)\), which gives the inverse function \(f^{-1}(x) = \log_{4}(x - 2)\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
One-to-One Functions
A one-to-one function is a function where each output corresponds to exactly one input, ensuring it has an inverse. This property is essential because only one-to-one functions have inverses that are also functions. Verifying this helps confirm that the inverse function exists.
An inverse function reverses the effect of the original function, swapping inputs and outputs. To find the inverse, you replace f(x) with y, interchange x and y, and then solve for y. The inverse function essentially 'undoes' the original function's operation.
Since the given function involves an exponential expression (4^(x+2)), its inverse will involve logarithms. Understanding that logarithms are the inverses of exponential functions is crucial for solving for the inverse function. Specifically, the inverse uses the logarithm base 4 to isolate the variable.