In Exercises 31–40, write the standard form of the equation of th...

Question

In Exercises 31–40, write the standard form of the equation of the circle with the given center and radius. Center (−3, −1), r = √3

Accepted Answer

for a circle with the following center and radius. Finance equation in standard form center equals negative eight comma 16 negative 16 and r is equal to square root of eight. So let's find the equation of a circle. The second form of a circle is given by x minus h squared plus y minus k squared equals r squared where h comma K. Is the center and R is the radius. So if we look at our center we can then say r H is equal to negative eight. R R actually not an R but r K is equal to -16 and our our is equal to the spirit of it. Let's go ahead and plug in all of our numbers. So x minus eight squared. So x minus negative eight squid plus y minus negative 16 squared equals the square of eight squared. Now we can simplify so we have x minus negative eight. That gives us x plus eight that is squeaked. Why minus negative 16 gives us Y plus 16 squared and finally you have the square of eight squared which is just equal to eight. This equation cannot simplify any further. So our equation is x minus eight squared plus y plus 16 squared equals eight. Make the answer to our problem as answer D. Okay I hope help you solve the problem. Thank you for watching. Goodbye

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In Exercises 31–40, write the standard form of the equation of the circle with the given center and radius. Center (−3, −1), r = √3