Determine the vertices and foci of the hyperbola y24−x2=1\frac{y^2}{4}-x^2=14y2−x2=1.

Vertices: ( 0 , 2 ) , ( 0 , − 2 ) \left(0,2\right),\left(0,-2\right) ( 0 , 2 ) , ( 0 , − 2 ) Foci: ( 0 , 5 ) , ( 0 , − 5 ) \left(0,\sqrt5\right),\left(0,-\sqrt5\right) ( 0 , 5 <path d="M95,702 c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14 c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54 c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10 s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429 c69,-144,104.5,-217.7,106.5,-221 l0 -0 c5.3,-9.3,12,-14,20,-14 H400000v40H845.2724 s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7 c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z M834 80h400000v40h-400000z"> ) , ( 0 , − 5 <path d="M95,702 c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14 c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54 c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10 s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429 c69,-144,104.5,-217.7,106.5,-221 l0 -0 c5.3,-9.3,12,-14,20,-14 H400000v40H845.2724 s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7 c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z M834 80h400000v40h-400000z"> )

8. Conic Sections

Hyperbolas at the Origin

College Algebra8. Conic SectionsHyperbolas at the Origin

Multiple Choice

Determine the vertices and foci of the hyperbola $\frac{y^2}{4}-x^2=1$ .

Vertices: $\left(2,0\right),\left(-2,0\right)$

Foci: $\left(\sqrt5,0\right),\left(-\sqrt5,0\right)$

Vertices: $\left(0,2\right),\left(0,-2\right)$

Foci: $\left(0,\sqrt5\right),\left(0,-\sqrt5\right)$

Vertices: $\left(1,0\right),\left(-1,0\right)$

Foci: $\left(5,0\right),\left(-5,0\right)$

Vertices: $\left(0,1\right),\left(0,-1\right)$

Foci: $\left(0,5\right),\left(0,-5\right)$

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Determine the vertices and foci of the hyperbola $\frac{y^2}{4}-x^2=1$ .

My Courses

Chemistry

Biology

Math

Physics

Business

Social Sciences

Programming

Product & Marketing

Determine the vertices and foci of the hyperbola ﻿y24−x2=1\frac{y^2}{4}-x^2=14y2​−x2=1﻿.

Determine the vertices and foci of the hyperbola $\frac{y^2}{4}-x^2=1$ .