Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
4. Polynomial Functions
Zeros of Polynomial Functions
Problem 84b
Textbook Question
Determine the different possibilities for the numbers of positive, negative, and nonreal complex zeros of each function. See Example 7. ƒ(x)=3x^4+2x^3-8x^2-10x-1

1
<Step 1: Identify the degree of the polynomial.> The given function is \( f(x) = 3x^4 + 2x^3 - 8x^2 - 10x - 1 \). The degree of this polynomial is 4, which means there are 4 zeros in total, considering multiplicity and complex numbers.
<Step 2: Apply Descartes' Rule of Signs for positive real zeros.> Count the number of sign changes in \( f(x) \). The signs of the coefficients are: +, +, -, -, -. There are two sign changes (from + to - and from - to -), indicating there could be 2 or 0 positive real zeros.
<Step 3: Apply Descartes' Rule of Signs for negative real zeros.> Consider \( f(-x) = 3(-x)^4 + 2(-x)^3 - 8(-x)^2 - 10(-x) - 1 \), which simplifies to \( 3x^4 - 2x^3 - 8x^2 + 10x - 1 \). The signs are +, -, -, +, -, showing three sign changes, indicating there could be 3 or 1 negative real zeros.
<Step 4: Determine the possibilities for nonreal complex zeros.> Since the total number of zeros is 4, and complex zeros occur in conjugate pairs, the possibilities for nonreal complex zeros are determined by the remaining zeros after accounting for the real zeros. If there are 2 positive and 1 negative real zero, there is 1 pair of complex zeros. If there are 0 positive and 3 negative real zeros, there is 1 pair of complex zeros.
<Step 5: Summarize the possibilities.> The possible combinations of zeros are: (a) 2 positive, 1 negative, and 1 pair of complex zeros; (b) 0 positive, 3 negative, and 1 pair of complex zeros. These combinations account for all 4 zeros of the polynomial.
Recommended similar problem, with video answer:

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
5mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Fundamental Theorem of Algebra
The Fundamental Theorem of Algebra states that every non-constant polynomial function of degree n has exactly n roots in the complex number system, counting multiplicities. This means that for a polynomial like f(x) = 3x^4 + 2x^3 - 8x^2 - 10x - 1, there will be four roots, which can be real or complex.
Recommended video:
Guided course
Introduction to Algebraic Expressions
Descarte's Rule of Signs
Descarte's Rule of Signs provides a method to determine the number of positive and negative real roots of a polynomial by analyzing the sign changes in the function's coefficients. For positive roots, count the sign changes in f(x), and for negative roots, count the sign changes in f(-x). This helps in predicting the nature of the roots.
Recommended video:
Guided course
Cramer's Rule - 2 Equations with 2 Unknowns
Complex Conjugate Root Theorem
The Complex Conjugate Root Theorem states that if a polynomial has real coefficients, any nonreal complex roots must occur in conjugate pairs. This means if a + bi is a root, then a - bi is also a root. This theorem is essential for understanding the distribution of roots when analyzing polynomials with real coefficients.
Recommended video:
Complex Conjugates
Related Videos
Related Practice