Identify each equation without completing the square.
$y^2+8x+6y+25=0$

Verified step by step guidance

1. Start by recognizing the general form of a conic section equation. The given equation is \( y^2 + 8x + 6y + 25 = 0 \). This resembles the general form of a parabola, \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \), where either \( A = 0 \) or \( C = 0 \).
2. In the given equation, notice that there is no \( x^2 \) term, which means \( A = 0 \). This suggests that the equation could represent a parabola that opens horizontally.
3. Next, identify the coefficients: \( A = 0 \), \( B = 0 \), \( C = 1 \), \( D = 8 \), \( E = 6 \), and \( F = 25 \). Since \( C \neq 0 \) and \( A = 0 \), this confirms that the equation is a parabola.
4. To further analyze the equation, rearrange it to isolate the \( y \) terms: \( y^2 + 6y = -8x - 25 \). This form helps in identifying the vertex and direction of the parabola.
5. Finally, recognize that the equation is in a form that can be transformed into the standard form of a parabola by completing the square on the \( y \) terms, but since the task is to identify without completing the square, we conclude that the equation represents a horizontally oriented parabola.