Solve each polynomial inequality in Exercises 1–42 and graph the solution set on a real number line. Express each solution set in interval notation. (x+1)(x+2)(x+3)≥0
Ch. 3 - Polynomial and Rational Functions

Chapter 4, Problem 29
Find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utility, use it to graph the function and verify the real zeros and the given function value. n=4; i and 3i are zeros; f(-1) = 20
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Identify the given zeros of the polynomial. Since the polynomial has real coefficients and the zeros include complex numbers \(i\) and \$3i\(, their conjugates \)-i\( and \)-3i\( must also be zeros. So the zeros are \)i\(, \)-i\(, \)3i\(, and \)-3i$.
Write the factors corresponding to each zero. For zeros \(i\) and \(-i\), the factor is \((x - i)(x + i) = x^{2} + 1\). For zeros \$3i\( and \)-3i\(, the factor is \)(x - 3i)(x + 3i) = x^{2} + 9$.
Form the polynomial as the product of these quadratic factors multiplied by a constant \(a\): \(f(x) = a(x^{2} + 1)(x^{2} + 9)\).
Use the given function value \(f(-1) = 20\) to find the constant \(a\). Substitute \(x = -1\) into the polynomial: \(f(-1) = a((-1)^{2} + 1)((-1)^{2} + 9) = a(1 + 1)(1 + 9) = a(2)(10) = 20\).
Solve for \(a\) from the equation \$20 = 20a\( to find the value of \)a\(. Then write the final polynomial function \)f(x)\( with this value of \)a$.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Complex Conjugate Root Theorem
For polynomials with real coefficients, non-real complex roots always come in conjugate pairs. If i is a root, then -i must also be a root. This ensures the polynomial remains with real coefficients when expanded.
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Constructing Polynomials from Roots
A polynomial can be formed by multiplying factors corresponding to its roots. For roots r, the factor is (x - r). Given roots i, -i, 3i, and -3i, the polynomial is the product of (x - i)(x + i)(x - 3i)(x + 3i), which simplifies to a polynomial with real coefficients.
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Using a Given Function Value to Find Leading Coefficient
After forming the polynomial with unknown leading coefficient a, substitute the given x-value (here, x = -1) and set the polynomial equal to the given function value (f(-1) = 20). Solving for a determines the exact polynomial.
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