Textbook QuestionSolve each equation in Exercises 1 - 14 by factoring. x^2 = 8x - 15211views1comments
Textbook QuestionMatch the equation in Column I with its solution(s) in Column II. x^2 - 5 = 0207views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Which equation is set up for direct use of the zero-factor property? Solve it287views
Textbook QuestionAnswer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. Find two consecutive integers whose product is 110.550views1rank
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. Find two consecutive even integers whose product is 168.205views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Only one of the equations does not require Step 1 of the method for completing the square described in this section. Which one is it? Solve it.216views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Only one of the equations is set up so that the values of a, b, and c can be determined immediately. Which one is it? Solve it.200views
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. The sum of the squares of two consecutive odd integers is 202. Find the integers236views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 3x^2 = 27374views
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. The sum of the squares of two consecutive even integers is 52. Find the integers.224views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 5x^2 = 45339views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 2x^2 - x = 15253views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. -6x^2 + 7x = -10251views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 3x^2 - 1 = 47463views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 2x^2 - 5 = - 55243views
Textbook QuestionSolve each problem. See Examples 1 and 2. Dimensions of a Square. The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in.2. Find the lengths of the sides of the two squares.456views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 9x^2 - 12x + 4 = 0330views
Textbook QuestionSolve each problem. See Examples 1. Dimensions of a Parking Lot. A parking lot has a rectangular area of 40,000 yd2. The length is 200 yd more than twice the width. Find the dimensions of the lot.244views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 36x^2 + 60x + 25 = 0208views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (x - 3)^2 = - 5326views
Textbook QuestionSolve each equation using the square root property. See Example 2. 48 - x^2 = 0334views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (3x + 2)^2 = 9203views
Textbook QuestionManufacturing to Specifications. A manufacturing firm wants to package its product in a cylindrical container 3 ft high with surface area 8π ft2. What should the radius of the circular top and bottom of the container be? (Hint: The surface area consists of the circular top and bottom and a rectangle that represents the side cut open vertically and unrolled.)239views
Textbook QuestionSolve each equation using the square root property. See Example 2. x^2 = -400303views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (4x - 1)^2 = 16237views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (8x - 3)^2 = 5220views
Textbook QuestionRadius of a CanA can of Blue Runner Red Kidney Beans has surface area 371 cm^2. Its height is 12 cm. What is the radius of the circular top? Round to the nearest hun-dredth.290views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. x^2 - 7x + 12 = 0198views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 + 3x488views
Textbook QuestionSolve each problem. See Example 2. Length of a WalkwayA nature conservancy group decides to construct a raised wooden walkway through a wetland area. To enclose the most interesting part of the wetlands, the walkway will have the shape of a right triangle with one leg 700 yd longer than the other and the hypotenuse 100 yd longer than the longer leg. Find the total length of the walkway.293views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - 7x354views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. x^2 - 2x - 2 = 0459views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. 2x^2 + x = 10258views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - (2/3)x375views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - (1/3)x374views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. -3x^2 + 6x + 5 = 0228views
Textbook QuestionWhich equation has two real, distinct solutions? Do not actually solve. A. (3x-4)² = -9 B. (4-7x)² = 0 C. (5x-9)(5x-9) = 0 D. (7x+4)² = 11234views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. 3x^2 - 9x + 7 = 0392views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 - x - 1 = 0240views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 - 6x - 11 = 0258views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number and type of solutions. 16x² +3 = -26x173views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 + 4x + 1 = 0286views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 - 6x = -7240views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 = 2x - 5216views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 - 5x + 6 = 0242views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 + 3x - 1 = 0223views
Textbook QuestionSolve each problem. Dimensions of a Right TriangleThe shortest side of a right triangle is 7 in. shorter than the middle side, while the longest side (the hypot-enuse) is 1 in. longer than the middle side. Find the lengths of the sides.190views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. 2/3x^2 + 1/4x = 3294views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. (4x - 1)(x + 2) = 4x363views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. 3x^2 - 5x - 10 = 0370views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. x^2 + 8x + 15 = 0274views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. x^2 + 5x + 3 = 0704views
Textbook QuestionSolve each cubic equation using factoring and the quadratic formula. See Example 7. x^3 - 27 = 0601views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. 3x^2 - 3x - 4 = 0306views
Textbook QuestionSolve each cubic equation using factoring and the quadratic formula. See Example 7. x^3 + 64 = 0329views
Textbook QuestionSolve each equation in Exercises 68–70 using the quadratic formula. 2x^2 = 3-4x322views
Textbook QuestionIn Exercises 71–72, without solving the given quadratic equation, determine the number and type of solutions. 9x^2 = 2-3x373views
Textbook QuestionSolve each equation in Exercises 73–81 by the method of your choice. 3x^2-7x+1 =0244views
Textbook QuestionSolve each equation for the specified variable. (Assume no denominators are 0.) See Example 8. r = r_0+(1/2)at^2, for t218views
Textbook QuestionSolve each equation in Exercises 73–81 by the method of your choice. (x-3)^2 - 25 = 0307views
Textbook QuestionSolve each equation for the specified variable. (Assume no denominators are 0.) See Example 8. h = -16t^2+v_0t+s_0, for t210views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. 2x^2 - 11x + 3 = 0273views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. x^2 - 2x + 1 = 0246views
Textbook QuestionFor each equation, (b) solve for y in terms of x. See Example 8. 4x^2 - 2xy + 3y^2 = 2376views
Textbook QuestionFor each equation, (a) solve for x in terms of y. See Example 8. 2x^2 + 4xy - 3y^2 = 2211views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. x^2 - 3x - 7 = 0385views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 2x^2 - x = 1265views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 3x^2 + 5x + 2 = 0240views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 4x^2 = -6x + 3388views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 8x^2 - 72 = 0276views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (2x + 3)(x + 4) = 1314views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (2x - 5)(x + 1) = 2228views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (3x - 4)^2 = 16219views
Textbook QuestionAnswer each question. Find the values of a, b, and c for which the quadratic equation. ax^2 + bx + c = 0 has the given numbers as solutions. (Hint: Use the zero-factor property in reverse.) 4, 5490views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 3x^2 - 12x + 12 = 0297views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. x^2 - 4x + 29 = 0232views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. x^2 = 4x - 7236views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 2x^2 - 7x = 0217views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 1/x + 1/(x + 2) = 1/3257views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = x^2 - 4x - 5243views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = - (x + 1)^2 + 4398views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y = 2x^2 - 3x and y = 2355views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y = 5x^2 + 3x and y = 2261views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y1 = 2x^2 + 5x - 4, y2 = - x^2 + 15x - 10, and y1 - y2 = 0382views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y1 = - x^2 + 4x - 2, y2 = - 3x^2 + x - 1, and y1 - y2 = 0332views
Textbook QuestionWhen the sum of 6 and twice a positive number is subtracted from the square of the number, 0 results. Find the number.294views
Textbook QuestionWhen the sum of 1 and twice a negative number is subtracted from twice the square of the number, 0 results. Find the number.241views
Textbook QuestionUse specific values for x and y to show that, in general, 1/x + 1/y is not equivalent to 1 / x + y.71views
Multiple ChoiceWrite the given quadratic equation in standard form. Identify a, b, and c. −4x2+x=8-4x^2+x=8−4x2+x=8349views5rank
Multiple ChoiceSolve the given quadratic equation by factoring. 3x2+12x=03x^2+12x=03x2+12x=0279views5rank2comments
Multiple ChoiceSolve the given equation by factoring. 2x2+7x+6=02x^2+7x+6=02x2+7x+6=0249views1comments