Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
1:19 minutes
Problem 37a
Textbook Question
Textbook QuestionIn Exercises 35–54, solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? A = (1/2)bh for b
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Algebraic Manipulation
Algebraic manipulation involves rearranging equations to isolate a specific variable. This process includes operations such as addition, subtraction, multiplication, and division applied to both sides of the equation. Understanding how to manipulate formulas is essential for solving for a variable, as it allows one to express the variable in terms of others.
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Area of a Triangle
The formula A = (1/2)bh represents the area of a triangle, where 'A' is the area, 'b' is the base, and 'h' is the height. This formula is derived from the concept that the area of a triangle is half the product of its base and height. Recognizing this formula helps in understanding the geometric context of the problem and the significance of the variables involved.
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Systems of Inequalities
Solving for a Variable
Solving for a variable means finding an expression that represents that variable in terms of others. In this case, we need to isolate 'b' in the equation A = (1/2)bh. This involves reversing the operations applied to 'b' and may require multiplying or dividing by other terms in the equation, which is a fundamental skill in algebra.
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