Let U = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13}, M = {0, 2, 4, 6, 8},
N = {1, 3, 5, 7, 9, 11, 13}, Q = {0, 2, 4, 6, 8, 10, 12}, and R = {0, 1, 2, 3, 4}.Use these sets to find each of the following. Identify any disjoint sets. {x | x ∈ U, x ∉ R}
Verified step by step guidance
1
Identify the universal set U = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13\}.
Identify the set R = \{0, 1, 2, 3, 4\}.
Determine the elements in U that are not in R by finding the set difference U - R.
The set difference U - R is \{x | x \in U, x \notin R\}.
List the elements in U that are not in R: \{5, 6, 7, 8, 9, 10, 11, 12, 13\}.
Recommended similar problem, with video answer:
Verified Solution
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
2m
Play a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Set Theory
Set theory is a fundamental branch of mathematics that deals with the study of sets, which are collections of distinct objects. In this context, understanding how to define and manipulate sets is crucial for solving problems involving unions, intersections, and differences of sets. For example, knowing how to express a set using set-builder notation, as seen in the question, is essential for identifying elements that belong to or exclude certain sets.
Disjoint sets are sets that have no elements in common; their intersection is the empty set. Recognizing disjoint sets is important in this problem as it helps in understanding the relationships between the given sets M, N, Q, and R. For instance, if two sets are disjoint, any operation involving them, such as union or intersection, will yield predictable results, simplifying the analysis of the overall problem.
The complement of a set refers to the elements that are not in the set but are in the universal set. In this question, the expression {x | x ∈ U, x ∉ R} represents the complement of set R within the universal set U. Understanding how to find the complement is essential for determining which elements belong to U but are excluded from R, thereby aiding in the overall solution of the problem.