Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Powers of i
1:16 minutes
Problem 93
Textbook Question
Textbook QuestionSimplify each power of i. i^23
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Imaginary Unit (i)
The imaginary unit 'i' is defined as the square root of -1. It is a fundamental concept in complex numbers, allowing for the extension of the real number system to include solutions to equations that do not have real solutions, such as x^2 + 1 = 0. Powers of 'i' cycle through a predictable pattern: i^1 = i, i^2 = -1, i^3 = -i, and i^4 = 1.
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Powers of i
Powers of i
The powers of 'i' exhibit a cyclical behavior every four terms. Specifically, i^1 = i, i^2 = -1, i^3 = -i, and i^4 = 1. This cycle repeats, meaning that to simplify higher powers of 'i', one can reduce the exponent modulo 4. For example, to simplify i^23, we calculate 23 mod 4, which equals 3, leading to i^23 = i^3 = -i.
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Powers of i
Modulo Operation
The modulo operation finds the remainder of division of one number by another. In the context of simplifying powers of 'i', it helps determine the equivalent lower power by reducing the exponent. For instance, when calculating i^23, we use 23 mod 4 to find the remainder, which is 3, indicating that i^23 is equivalent to i^3. This technique is essential for efficiently handling large exponents.
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