Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
3. Functions
Intro to Functions & Their Graphs
Problem 63d
Textbook Question
Determine whether each function is even, odd, or neither. See Example 5. ƒ(x)=x+1/x^5
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1
Step 1: Recall the definitions of even and odd functions. A function \( f(x) \) is even if \( f(-x) = f(x) \) for all \( x \) in the domain. A function is odd if \( f(-x) = -f(x) \) for all \( x \) in the domain.
Step 2: Substitute \( -x \) into the function \( f(x) = x + \frac{1}{x^5} \) to find \( f(-x) \). This gives \( f(-x) = -x + \frac{1}{(-x)^5} \).
Step 3: Simplify \( f(-x) \). Since \((-x)^5 = -x^5\), we have \( f(-x) = -x - \frac{1}{x^5} \).
Step 4: Compare \( f(-x) \) with \( f(x) \). Check if \( f(-x) = f(x) \) to determine if the function is even, or if \( f(-x) = -f(x) \) to determine if the function is odd.
Step 5: Conclude whether the function is even, odd, or neither based on the comparison in Step 4.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Even Functions
A function is classified as even if it satisfies the condition f(-x) = f(x) for all x in its domain. This means that the graph of the function is symmetric with respect to the y-axis. A common example of an even function is f(x) = x^2, where substituting -x yields the same output as substituting x.
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Odd Functions
A function is considered odd if it meets the condition f(-x) = -f(x) for all x in its domain. This indicates that the graph of the function is symmetric with respect to the origin. An example of an odd function is f(x) = x^3, where substituting -x results in the negative of the output for x.
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Neither Even Nor Odd Functions
A function is classified as neither even nor odd if it does not satisfy the conditions for either classification. This means that f(-x) does not equal f(x) and also does not equal -f(x). An example is f(x) = x + 1, where substituting -x yields a different result that does not fit either symmetry.
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