Find the sum. Express your answer in standard form. 5 ( 4 + 7 i ) + 6 ( 3 − 2 i ) 5\left(4+7i\right)+6\left(3-2i\right) 5 ( 4 + 7 i ) + 6 ( 3 − 2 i )

Hey, everyone. Let's take a look at this practice problem. So I wanna find the sum of these two complex numbers and express my answer in standard form. So here I have 5 times 4+7i+6 times 3 minus 2i. So let's go ahead and get rid of those parentheses. Now I actually have coefficients on the outside of both of these complex numbers, so that means I need to go ahead and distribute that in before I go any further. So for my first term, I have 4 5 times 4, which is going to give me 20, and then 5 times 7 I, I, which is going to give me 35 I. Then I have positive 6 multiplying my 3, which is going to give me a positive 18. And then lastly, I have 6 times negative 2 I, which is gonna give me a negative 12 I. Now I can go ahead and combine like terms. So I have my 20 and my 18, which are gonna combine to give me positive 38. And then I have my 35 I and then my minus 12 I, which is going to give me a positive 23 I. Now checking that my answer is in standard form, a+bi, and it is. So my final answer is 38 +23i. Let me know if you have any questions.