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Ch. 4 - Exponential and Logarithmic Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
Chapter 5, Problem 83

In Exercises 83–88, let logb 2 = A and logb 3 = C and Write each expression in terms of A and C.
logb (3/2)

Verified step by step guidance
1
Recall the logarithm property for division: logb(32) = logb3 - logb2. This means the log of a quotient is the difference of the logs.
Substitute the given values: since logb2 = A and logb3 = C, replace these in the expression.
Write the expression as logb(32) = C - A.
This expresses logb(32) entirely in terms of the variables A and C as requested.
No further simplification is needed since the problem asks only to write the expression in terms of A and C.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Properties of Logarithms

Logarithms have specific properties that simplify expressions, such as the quotient rule: log_b(x/y) = log_b(x) - log_b(y). This allows us to rewrite complex logarithmic expressions as differences or sums of simpler logs.
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Change of Base Property

Change of Base and Logarithm Notation

Understanding the notation log_b(x) means the logarithm of x with base b is crucial. Given log_b(2) = A and log_b(3) = C, we can express other logarithms with base b in terms of A and C by applying logarithmic properties.
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Change of Base Property

Expressing Logarithmic Expressions in Terms of Variables

When given variables representing logarithms, such as A and C, the goal is to rewrite expressions like log_b(3/2) using these variables. This involves substituting and simplifying using known values and logarithmic rules.
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Radical Expressions with Variables