Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Rational Equations
1:26 minutes
Problem 11a
Textbook Question
Textbook QuestionDetermine the values of the variable that cannot possibly be solutions of each equation. Do not solve. See Examples 1 and 2. (5/(2x+3))-(1/(x-6))=0
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Undefined Values
In algebra, certain values for a variable can make an expression undefined, typically when they result in division by zero. For example, in the equation (5/(2x+3))-(1/(x-6))=0, the expressions 2x+3 and x-6 cannot equal zero, as this would lead to undefined terms in the equation.
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Domain of a Function
The domain of a function refers to all possible input values (or 'x' values) that can be used without causing any undefined behavior. In the context of the given equation, identifying the domain involves determining which values of 'x' would lead to division by zero, thus excluding them from potential solutions.
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Rational Expressions
Rational expressions are fractions where the numerator and denominator are polynomials. In the equation provided, both (5/(2x+3)) and (1/(x-6)) are rational expressions. Understanding their behavior, particularly how to identify restrictions on 'x' that prevent division by zero, is crucial for analyzing the equation without solving it.
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