Factor each polynomial. See Examples 5 and 6. (b+3)3-27
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Recognize that the expression \( (b+3)^3 - 27 \) is a difference of cubes, since \$27\( can be written as \)3^3$.
Recall the difference of cubes formula: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\).
Identify \(a = (b+3)\) and \(b = 3\) in the expression \( (b+3)^3 - 3^3 \).
Apply the formula: write the factorization as \(((b+3) - 3)((b+3)^2 + (b+3)(3) + 3^2)\).
Simplify each factor: simplify \(((b+3) - 3)\) to \(b\), expand and simplify the quadratic expression inside the second factor.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Difference of Cubes
The difference of cubes formula states that a³ - b³ = (a - b)(a² + ab + b²). It is used to factor expressions where two perfect cubes are subtracted. Recognizing the structure allows for straightforward factoring of cubic expressions.
To apply the difference of cubes formula, each term must be a perfect cube. This involves recognizing expressions like (b+3)³ and 27, since 27 = 3³. Understanding how to rewrite terms as cubes is essential for correct factoring.
Factoring polynomials involves breaking down expressions into simpler factors. Techniques include factoring out common terms, grouping, and special formulas like difference of cubes. Mastery of these methods helps simplify and solve polynomial equations.