Factor each polynomial. See Examples 5 and 6. (p-2q)2-100
Verified step by step guidance
1
Recognize that the given expression \( (p-2q)^2 - 100 \) is a difference of squares, since it can be written as \( (p-2q)^2 - 10^2 \).
Recall the difference of squares formula: \( a^2 - b^2 = (a - b)(a + b) \). Here, \( a = p - 2q \) and \( b = 10 \).
Apply the formula by substituting \( a \) and \( b \) into it: \( (p - 2q - 10)(p - 2q + 10) \).
Write the factored form clearly as \( (p - 2q - 10)(p - 2q + 10) \).
Verify by expanding the factors to ensure they multiply back to the original expression.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
2m
Play a video:
0 Comments
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Difference of Squares
The difference of squares is a factoring technique used when an expression is in the form a² - b². It factors into (a - b)(a + b). Recognizing this pattern helps simplify expressions like (p - 2q)² - 100 by identifying a = (p - 2q) and b = 10.
Solving Quadratic Equations by Completing the Square
Binomial Squares
A binomial square is an expression of the form (x ± y)², which expands to x² ± 2xy + y². Understanding how to expand and recognize binomial squares is essential for factoring or simplifying expressions involving squared binomials, such as (p - 2q)².
Solving Quadratic Equations by Completing the Square
Polynomial Factoring
Polynomial factoring involves rewriting a polynomial as a product of simpler polynomials. Mastery of various factoring methods, including factoring by grouping, special products, and difference of squares, is crucial for breaking down complex expressions into factors.