Oil is introduced to a cylindrical vessel until it reaches a depth of 36 36 36 ft. The cross-sectional area of the vessel is 15 15 15 ft 2 . A drain with an area of 2 2 2 ft 2 located at the bottom of the vessel is opened at t = 0 t=0 t = 0 s. At time t ≥ 0 t\geq{0} t ≥ 0 , the depth of the oil is represented by the function d ( t ) = ( 6 − 0.13 t ) 2 d\left(t\right)=\left(6-0.13t\right)^2 d ( t ) = ( 6 − 0.13 t ) 2 . Does this function provide a depth of 36 36 36 ft as specified at t = 0 t=0 t = 0 s?

Yes, the function provides a depth of 36 36 36 ft at t = 0 t=0 t = 0 s.

No, the function does not provide a depth of 36 36 36 ft at t = 0 t=0 t = 0 s.

Oil is introduced to a cylindrical vessel until it...

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