A streetlight of height H H is fixed at point A A on the ground. A person walks away from the streetlight along a straight path at a constant speed. Let B B be the point where the person is currently standing, and let C C be the distance between points A A and B B on the ground. Define θ \theta as the angle between the streetlight and the line connecting the top of the streetlight to point B B . Find d θ d C \frac{d\theta}{dC} .

d θ d C = H H 2 + C 2 \frac{d\theta}{dC}=\frac{H}{H^2+C^2}

d θ d C = − C H 2 + C 2 \frac{d\theta}{dC}=-\frac{C}{H^2+C^2}

d θ d C = − H H 2 + C 2 \frac{d\theta}{dC}=-\frac{H}{H^2+C^2}

d θ d C = C H 2 + C 2 \frac{d\theta}{dC}=\frac{C}{H^2+C^2}

A streetlight of height HH is fixed at point AA on the ground. A ...

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