A city's water pumping station operates based on the energy consumption model E ( t ) = 500 t + 1800 π cos ⁡ ( π t 6 ) E\left(t\right)=500t+\frac{1800}{\pi}\cos\left(\frac{\pi t}{6}\right) , where E ( t ) E\left(t\right) is the total energy in kilowatt-hour (kWh), and t ≥ 0 t≥0 is measured in hours from midnight. At what time of day does the energy consumption rate first reach its minimum? What is the minimum rate of energy consumption?

3 AM 3\text{ AM} 3 AM ; 200 kW 200\text{ kW} 200 kW

9 AM 9\text{ AM} ; 200 kW 200\text{ kW} 200 kW

9 AM 9\text{ AM} ; 800 kW 800\text{ kW}

3 AM 3\text{ AM} ; 800 kW 800\text{ kW}

A city's water pumping station operates based on t...

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