Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
2. Intro to Derivatives
Derivatives as Functions
Problem 3.1.64a
Textbook Question
The following table gives the distance f(t) fallen by a smoke jumper seconds after she opens her chute. <IMAGE>
a. Use the forward difference quotient with ℎ = 0.5 to estimate the velocity of the smoke jumper at t=2 seconds.
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1
Step 1: Understand the forward difference quotient. The forward difference quotient is a method to estimate the derivative of a function at a certain point. It is given by the formula: \( f'(t) \approx \frac{f(t+h) - f(t)}{h} \), where \( h \) is a small increment.
Step 2: Identify the values needed from the table. You need the distance \( f(t) \) at \( t = 2 \) seconds and \( f(t+h) \) at \( t = 2.5 \) seconds, since \( h = 0.5 \).
Step 3: Substitute the values into the forward difference quotient formula. Use the values from the table for \( f(2) \) and \( f(2.5) \) to calculate the approximate velocity.
Step 4: Calculate the difference in distances. Find \( f(2.5) - f(2) \) to determine how much the distance has changed over the interval from \( t = 2 \) to \( t = 2.5 \).
Step 5: Divide the difference by \( h = 0.5 \). This will give you the estimated velocity of the smoke jumper at \( t = 2 \) seconds.
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