Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 4.R.87
Textbook Question
82–89. Comparing growth rates Determine which of the two functions grows faster, or state that they have comparable growth rates.
eˣ and 3ˣ

1
Identify the two functions to compare: f(x) = e^x and g(x) = 3^x.
Take the limit of the ratio of the two functions as x approaches infinity: lim (x → ∞) (e^x / 3^x).
Simplify the limit by rewriting it as lim (x → ∞) (e^x / (3^x)) = lim (x → ∞) (e^x / e^(x ln(3))) = lim (x → ∞) (e^(x(1 - ln(3)))) using properties of exponents.
Analyze the exponent: If 1 - ln(3) is positive, the limit approaches infinity, indicating e^x grows faster; if negative, it approaches 0, indicating 3^x grows faster; if zero, they grow at the same rate.
Calculate the value of 1 - ln(3) to determine the growth rate comparison.
Recommended similar problem, with video answer:

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
4mPlay a video:
Was this helpful?