Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
3. Techniques of Differentiation
The Chain Rule
Problem 3.7.79
Textbook Question
Applying the Chain Rule Use the data in Tables 3.4 and 3.5 of Example 4 to estimate the rate of change in pressure with respect to time experienced by the runner when she is at an altitude of 13,330 ft. Make use of a forward difference quotient when estimating the required derivatives.
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1
Identify the variables involved: let P be the pressure and t be the time. We need to find the rate of change of pressure with respect to time, denoted as dP/dt.
Locate the relevant data in Tables 3.4 and 3.5 for the altitude of 13,330 ft. Extract the corresponding pressure values and their associated times.
Use the forward difference quotient formula to estimate the derivative: dP/dt ≈ (P(t + Δt) - P(t)) / Δt, where Δt is a small increment in time.
Substitute the pressure values from the tables into the forward difference quotient formula to compute the estimated rate of change.
Interpret the result in the context of the problem, considering how the pressure changes as the runner continues to move at the specified altitude.
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