Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
3. Techniques of Differentiation
The Chain Rule
Problem 3.57g
Textbook Question
Suppose that functions ƒ(x) and g(x) and their first derivatives have the following values at x = 0 and x = 1.
x ƒ(x) g(x) ƒ'(x) g'(x)
0 1 1 -3 1/2
1 3 5 1/2 -4
Find the first derivatives of the following combinations at the given value of x.
g. ƒ(x + g(x)), x = 0

1
To find the derivative of the composite function \( h(x) = f(x + g(x)) \), we will use the chain rule. The chain rule states that if you have a composite function \( h(x) = f(u(x)) \), then the derivative \( h'(x) = f'(u(x)) \cdot u'(x) \).
First, identify the inner function \( u(x) = x + g(x) \). The derivative of \( u(x) \) with respect to \( x \) is \( u'(x) = 1 + g'(x) \).
Next, evaluate \( u(x) \) at \( x = 0 \). Since \( g(0) = 1 \), we have \( u(0) = 0 + 1 = 1 \).
Now, find \( f'(u(x)) \) at \( u(0) = 1 \). From the given data, \( f'(1) = \frac{1}{2} \).
Finally, apply the chain rule: \( h'(0) = f'(u(0)) \cdot u'(0) = f'(1) \cdot (1 + g'(0)) = \frac{1}{2} \cdot (1 + \frac{1}{2}) \).
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