- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Linearization
Problem 4.6.13
Textbook Question
Estimating speed Use the linear approximation given in Example 1 to answer the following questions.
If you travel one mile in 59 seconds, what is your approximate average speed? What is your exact speed?

1
Identify the relationship between distance, speed, and time. The formula for speed is given by \( v = \frac{d}{t} \), where \( v \) is speed, \( d \) is distance, and \( t \) is time.
Convert the given time from seconds to hours, since speed is typically measured in miles per hour (mph). There are 3600 seconds in an hour, so \( t = \frac{59}{3600} \) hours.
Use the linear approximation method to estimate the speed. Linear approximation involves using the derivative of a function to estimate the value of the function at a point close to a known value. Here, the function is \( v(t) = \frac{1}{t} \) and the derivative \( v'(t) = -\frac{1}{t^2} \).
Calculate the approximate speed using the linear approximation formula: \( v(t) \approx v(a) + v'(a)(t-a) \), where \( a \) is a point close to \( t \) for which \( v(a) \) is known. Choose \( a = 60 \) seconds (1 minute), where the speed is 60 mph.
Finally, calculate the exact speed using the formula \( v = \frac{d}{t} \) with \( d = 1 \) mile and \( t = \frac{59}{3600} \) hours to find the exact speed in mph.
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