Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
3. Techniques of Differentiation
The Chain Rule
Problem 3.27
Textbook Question
Find the derivatives of the functions in Exercises 1–42.
𝔂 = x² sin² (2x²)

1
Identify the function structure: The function is given as \( y = x^2 \sin^2(2x^2) \). This is a product of two functions: \( u(x) = x^2 \) and \( v(x) = \sin^2(2x^2) \).
Apply the product rule: The derivative of a product \( u(x)v(x) \) is \( u'(x)v(x) + u(x)v'(x) \). First, find the derivative of \( u(x) = x^2 \), which is \( u'(x) = 2x \).
Differentiate \( v(x) = \sin^2(2x^2) \) using the chain rule: Let \( w(x) = \sin(2x^2) \), so \( v(x) = w(x)^2 \). The derivative \( v'(x) = 2w(x)w'(x) \).
Find \( w'(x) \) using the chain rule: \( w(x) = \sin(2x^2) \), so \( w'(x) = \cos(2x^2) \cdot (4x) \) because the derivative of \( 2x^2 \) is \( 4x \).
Substitute back into the product rule: Combine \( u'(x) \), \( v(x) \), \( u(x) \), and \( v'(x) \) to find the derivative of the original function. Simplify the expression to complete the differentiation process.
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