Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
0. Functions
Common Functions
Problem 77f
Textbook Question
Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.
If , then .
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1
Step 1: Understand the definition of an inverse function. For a function \( f(x) \), its inverse \( f^{-1}(x) \) satisfies the condition \( f(f^{-1}(x)) = x \) and \( f^{-1}(f(x)) = x \).
Step 2: Consider the given function \( f(x) = x^2 + 1 \). To find its inverse, we would typically solve the equation \( y = x^2 + 1 \) for \( x \) in terms of \( y \).
Step 3: Rearrange the equation \( y = x^2 + 1 \) to solve for \( x \): \( x^2 = y - 1 \). Then, \( x = \pm \sqrt{y - 1} \).
Step 4: Notice that the expression \( x = \pm \sqrt{y - 1} \) implies that \( f(x) = x^2 + 1 \) is not one-to-one, as it does not pass the horizontal line test. Therefore, it does not have an inverse function over the entire set of real numbers.
Step 5: The statement \( f^{-1}(x) = \frac{1}{x^2 + 1} \) is incorrect because the expression given does not satisfy the conditions for an inverse function of \( f(x) = x^2 + 1 \). A counterexample is that substituting \( x = 0 \) into \( f(x) \) gives \( f(0) = 1 \), but substituting \( x = 1 \) into \( f^{-1}(x) \) gives \( \frac{1}{2} \), which does not satisfy the inverse condition.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Function and Inverse Function
A function maps each input to a single output, while an inverse function reverses this mapping. For a function f(x), its inverse f⁻¹(x) satisfies the condition f(f⁻¹(x)) = x for all x in the domain of f⁻¹. Understanding this relationship is crucial for determining whether the proposed inverse function is correct.
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One-to-One Function
A function is one-to-one (injective) if it never assigns the same value to two different domain elements. This property is essential for a function to have an inverse. If f(x) = x² + 1 is not one-to-one, it cannot have a valid inverse, which is a key consideration in evaluating the given statements.
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Counterexample
A counterexample is a specific case that disproves a statement or proposition. In the context of functions, providing a counterexample involves finding an input that leads to the same output for different inputs, thereby demonstrating that the function is not one-to-one. This is a critical tool in validating or refuting claims about functions and their inverses.
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