Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
3. Techniques of Differentiation
The Chain Rule
Problem 16
Textbook Question
5–24. For each of the following composite functions, find an inner function u=g(x) and an outer function y=f(u) such that y=f(g(x)). Then calculate dy/dx.
y = (5x²+11x)^4/3

1
Identify the inner function and the outer function: Let the inner function be \( u = g(x) = 5x^2 + 11x \) and the outer function be \( y = f(u) = u^{4/3} \).
Differentiate the inner function \( u = g(x) \) with respect to \( x \): \( \frac{du}{dx} = \frac{d}{dx}(5x^2 + 11x) \).
Differentiate the outer function \( y = f(u) \) with respect to \( u \): \( \frac{dy}{du} = \frac{d}{du}(u^{4/3}) \).
Apply the chain rule to find \( \frac{dy}{dx} \): \( \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \).
Substitute the expressions for \( \frac{dy}{du} \) and \( \frac{du}{dx} \) into the chain rule formula to express \( \frac{dy}{dx} \) in terms of \( x \).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Composite Functions
A composite function is formed when one function is applied to the result of another function. In the context of the given problem, we need to identify an inner function g(x) and an outer function f(u) such that the overall function can be expressed as y = f(g(x)). Understanding how to decompose a function into its components is essential for differentiation.
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Chain Rule
The chain rule is a fundamental principle in calculus used to differentiate composite functions. It states that if y = f(g(x)), then the derivative dy/dx can be calculated as dy/dx = f'(g(x)) * g'(x). This rule allows us to find the derivative of complex functions by breaking them down into simpler parts, making it crucial for solving the problem.
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Power Rule
The power rule is a basic differentiation rule that states if y = x^n, then dy/dx = n*x^(n-1). In the context of the given function, which involves a power of a polynomial, applying the power rule to the outer function will be necessary to compute the derivative correctly. This rule simplifies the process of differentiation for polynomial expressions.
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