Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
0. Functions
Properties of Functions
Problem 1.13
Textbook Question
In Exercises 9–16, determine whether the function is even, odd, or neither.
𝔂 = x⁴ + 1
x³ - 2x

1
To determine if a function is even, odd, or neither, we need to analyze its symmetry properties. A function y = f(x) is even if f(-x) = f(x) for all x in the domain, and it is odd if f(-x) = -f(x) for all x in the domain.
Start by substituting -x into the function y = x^4 + 1x^3 - 2x. This gives us y = (-x)^4 + 1(-x)^3 - 2(-x).
Simplify the expression: (-x)^4 = x^4, (-x)^3 = -x^3, and -2(-x) = 2x. So, the expression becomes y = x^4 - x^3 + 2x.
Compare the simplified expression y = x^4 - x^3 + 2x with the original function y = x^4 + 1x^3 - 2x. Since f(-x) is not equal to f(x) and f(-x) is not equal to -f(x), the function is neither even nor odd.
Conclude that the function y = x^4 + 1x^3 - 2x is neither even nor odd based on the symmetry analysis.
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