Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 69
Textbook Question
Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.
lim_x→∞ log₂ x / log₃ x

1
Identify the limit to evaluate: lim_{x→∞} (log₂ x) / (log₃ x).
Check if the limit is in an indeterminate form. As x approaches infinity, both log₂ x and log₃ x approach infinity, resulting in the form ∞/∞.
Since the limit is in the indeterminate form ∞/∞, apply l'Hôpital's Rule, which states that you can take the derivative of the numerator and the derivative of the denominator.
Differentiate the numerator: the derivative of log₂ x is (1 / (x ln 2)). Differentiate the denominator: the derivative of log₃ x is (1 / (x ln 3)).
Rewrite the limit using the derivatives: lim_{x→∞} (1 / (x ln 2)) / (1 / (x ln 3)) and simplify the expression.
Recommended similar problem, with video answer:

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
3mPlay a video:
Was this helpful?