- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
0. Functions
Introduction to Functions
Problem 4.R.118a
Textbook Question
{Use of Tech} A family of superexponential functions Let ƒ(x) = (a + x)ˣ , where a > 0.
a. What is the domain of f (in terms of a)?

1
To determine the domain of the function \( f(x) = (a + x)^x \), we need to identify the values of \( x \) for which the expression is defined.
The base of the power, \( a + x \), must be positive because raising a negative number to a real power can result in a complex number, which is not within the scope of real-valued functions.
Therefore, we set the inequality \( a + x > 0 \) to ensure the base is positive.
Solving the inequality \( a + x > 0 \) gives \( x > -a \).
Thus, the domain of \( f(x) \) in terms of \( a \) is \( x > -a \).
Recommended similar problem, with video answer:

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
1mPlay a video:
Was this helpful?
Watch next
Master Introduction to Calculus Channel with a bite sized video explanation from Callie
Start learning