- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
1. Limits and Continuity
Finding Limits Algebraically
Problem 5
Textbook Question
Limits and Continuity
In Exercises 5 and 6, find the value that lim (x→0) g(x) must have if the given limit statements hold.
lim ((4―g(x)) / x ) = 1
x→0

1
First, understand that the problem involves finding the limit of a function as x approaches 0. The given limit statement is \( \lim_{{x \to 0}} \frac{{4 - g(x)}}{x} = 1 \).
Recognize that this is a limit problem involving a fraction where the numerator is \(4 - g(x)\) and the denominator is \(x\). As \(x\) approaches 0, the fraction approaches 1.
To solve for \(g(x)\), consider the form of the limit. For the limit to exist and equal 1, the numerator must approach 0 as \(x\) approaches 0. This implies that \(4 - g(x)\) must approach 0.
Set up the equation based on the above reasoning: \(4 - g(x) = 0\). Solve this equation to find \(g(x)\).
Conclude that for the limit to hold, \(g(x)\) must approach a specific value as \(x\) approaches 0. Solve the equation \(4 - g(x) = 0\) to find that value.
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