Lapse rates in the atmosphere Refer to Example 2. Concurrent measurements indicate that at an elevation of 6.1 km, the temperature is -10.3° C and at an elevation of 3.2km , the temperature is 8.0°C . Based on the Mean Value Theorem, can you conclude that the lapse rate exceeds the threshold value of 7°C/ km at some intermediate elevation? Explain.
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 101
Textbook Question
Use limit methods to determine which of the two given functions grows faster, or state that they have comparable growth rates.
x²⁰ ; 1.0001ˣ

1
Step 1: To compare the growth rates of the functions \( f(x) = x^{20} \) and \( g(x) = 1.0001^x \), we can use the concept of limits. Specifically, we will evaluate the limit of the ratio \( \frac{f(x)}{g(x)} \) as \( x \to \infty \).
Step 2: Set up the limit expression: \( \lim_{x \to \infty} \frac{x^{20}}{1.0001^x} \). This will help us determine which function grows faster.
Step 3: Analyze the behavior of the numerator \( x^{20} \) and the denominator \( 1.0001^x \) as \( x \to \infty \). The polynomial \( x^{20} \) grows at a polynomial rate, while the exponential function \( 1.0001^x \) grows at an exponential rate.
Step 4: Recall that exponential functions generally grow faster than polynomial functions as \( x \to \infty \). Therefore, we expect \( 1.0001^x \) to outpace \( x^{20} \) in growth.
Step 5: Conclude that if the limit \( \lim_{x \to \infty} \frac{x^{20}}{1.0001^x} = 0 \), then \( g(x) = 1.0001^x \) grows faster than \( f(x) = x^{20} \). If the limit were a non-zero constant, they would have comparable growth rates.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Limits
Limits are fundamental in calculus, representing the value that a function approaches as the input approaches a certain point. They are crucial for analyzing the behavior of functions at infinity or near specific points, allowing us to determine growth rates and continuity. In this context, limits help compare the growth of the two functions as x approaches infinity.
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Growth Rates
Growth rates describe how quickly a function increases as its input increases. In calculus, we often compare polynomial functions, like x²⁰, with exponential functions, like 1.0001ˣ, to determine which grows faster. Understanding the nature of these functions is essential for evaluating their limits and establishing their relative growth.
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Asymptotic Behavior
Asymptotic behavior refers to the behavior of functions as the input approaches infinity. It helps in classifying functions based on their growth rates, indicating whether one function dominates another in terms of growth. Analyzing the asymptotic behavior of x²⁰ and 1.0001ˣ will reveal which function grows faster as x becomes very large.
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