Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 4.6.53c
Textbook Question
Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.
c. If f(x) = mx + b, then the linear approximation to f at any point is L(x) = f(x).
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1
Understand that the linear approximation of a function f at a point a is given by L(x) = f(a) + f'(a)(x - a). This means we need to find the value of the function and its derivative at the point a.
For the function f(x) = mx + b, calculate the derivative f'(x) which is constant and equal to m, since the slope of a linear function is constant.
Choose a specific point a to evaluate the linear approximation. For example, let a = 0. Then, f(0) = b and f'(0) = m.
Substitute these values into the linear approximation formula: L(x) = b + m(x - 0) = mx + b, which simplifies to L(x) = f(x).
Conclude that the statement is true because the linear approximation L(x) at any point a for the linear function f(x) = mx + b is indeed equal to f(x).
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