Textbook Question
15–48. Derivatives Find the derivative of the following functions.
f(x) = 2^x/2^x+1
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Ch. 3 - Derivatives
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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Table of contents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 3, Problem 3.8.28
27–40. Implicit differentiation Use implicit differentiation to find dy/dx.
y = xe^y
Verified step by step guidance1
Start by differentiating both sides of the equation with respect to x. The equation is y = x * e^y.
Apply the product rule to the right side of the equation. The product rule states that d(uv)/dx = u'v + uv', where u = x and v = e^y.
Differentiate u = x with respect to x, which gives 1. Differentiate v = e^y with respect to x, which requires the chain rule: d(e^y)/dx = e^y * dy/dx.
Substitute the derivatives back into the product rule: d(x * e^y)/dx = 1 * e^y + x * e^y * dy/dx.
Set the derivative of the left side, dy/dx, equal to the derivative of the right side: dy/dx = e^y + x * e^y * dy/dx. Solve for dy/dx by isolating it on one side of the equation.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Implicit Differentiation
Implicit differentiation is a technique used to differentiate equations where the dependent and independent variables are not explicitly separated. Instead of solving for one variable in terms of the other, we differentiate both sides of the equation with respect to the independent variable, applying the chain rule as necessary. This method is particularly useful for equations that are difficult or impossible to rearrange.
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Finding The Implicit Derivative
Chain Rule
The chain rule is a fundamental principle in calculus that allows us to differentiate composite functions. It states that if a function y is defined as a function of u, which is in turn a function of x, then the derivative of y with respect to x can be found by multiplying the derivative of y with respect to u by the derivative of u with respect to x. This is essential in implicit differentiation when dealing with functions of y.
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05:02Intro to the Chain Rule
Exponential Functions
Exponential functions are mathematical functions of the form f(x) = a * e^(bx), where e is the base of natural logarithms, and a and b are constants. In the context of implicit differentiation, recognizing the properties of exponential functions, such as their derivatives, is crucial. The derivative of e^(y) with respect to x involves both the chain rule and the derivative of y, making it important to apply these concepts correctly.
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6:13Exponential Functions
Related Practice
Textbook Question
23–51. Calculating derivatives Find the derivative of the following functions.
y = sin x / 1 + cos x
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Textbook Question
If f is continuous at a, must f be differentiable at a?
452
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Textbook Question
Find the derivative of the following functions.
y = sin x + cos x
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Textbook Question
A water heater that has the shape of a right cylindrical tank with a radius of 1 ft and a height of 4 ft is being drained. How fast is water draining out of the tank (in ft³/min) if the water level is dropping at 6 min/in?
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Textbook Question
49–55. Derivatives of tower functions (or g^h) Find the derivative of each function and evaluate the derivative at the given value of a.
f (x) = (4 sin x+2)^cos x; a = π
170
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