Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Implicit Differentiation
Problem 3.8.58b
Textbook Question
58–59. Carry out the following steps.
b. Find the slope of the curve at the given point.
xy^5/2+x^3/2y=12; (4, 1)

1
First, understand that the problem requires finding the slope of the curve at a specific point, which involves calculating the derivative of the given equation implicitly.
The given equation is \( xy^{\frac{5}{2}} + x^{\frac{3}{2}}y = 12 \). To find the derivative, we will use implicit differentiation since the equation involves both x and y.
Differentiate both sides of the equation with respect to x. Remember to apply the product rule where necessary. For example, when differentiating \( xy^{\frac{5}{2}} \), treat it as a product of x and \( y^{\frac{5}{2}} \).
After differentiating, you will have an expression involving \( \frac{dy}{dx} \). Solve this expression for \( \frac{dy}{dx} \) to find the derivative, which represents the slope of the curve.
Finally, substitute the given point (4, 1) into the derivative expression to find the slope at that specific point.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Implicit Differentiation
Implicit differentiation is a technique used to differentiate equations where the dependent and independent variables are not explicitly separated. In this case, we differentiate both sides of the equation with respect to x, treating y as a function of x. This allows us to find dy/dx, which represents the slope of the curve at any point.
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Slope of a Curve
The slope of a curve at a given point is defined as the rate of change of the y-coordinate with respect to the x-coordinate at that point. Mathematically, it is represented by the derivative of the function at that point. For implicit functions, the slope can be found by evaluating dy/dx after applying implicit differentiation.
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Evaluating Derivatives at a Point
Once the derivative (dy/dx) is found using implicit differentiation, the next step is to evaluate it at a specific point, in this case, (4, 1). This involves substituting the x and y values into the derivative expression to calculate the exact slope of the curve at that point, providing insight into the curve's behavior.
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