Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Motion Analysis
Problem 18e
Textbook Question
Suppose the position of an object moving horizontally along a line after t seconds is given by the following functions s = f(t), where s is measured in feet, with s > 0 corresponding to positions right of the origin.
On what intervals is the speed increasing?
f(t) = 18t - 3t2; 0 ≤ t ≤ 8

1
Step 1: Understand that speed is the absolute value of velocity. To find when speed is increasing, we need to analyze the velocity function and its derivative.
Step 2: Find the velocity function v(t) by differentiating the position function f(t) with respect to time t. This gives v(t) = f'(t) = 18 - 6t.
Step 3: Determine when the velocity is increasing by finding the derivative of the velocity function, which is the acceleration a(t). So, a(t) = v'(t) = -6.
Step 4: Since the acceleration a(t) = -6 is constant and negative, the velocity is always decreasing. However, speed increases when velocity and acceleration have opposite signs.
Step 5: Analyze the intervals where velocity is negative (v(t) < 0) because speed increases when velocity is negative and decreasing. Solve 18 - 6t < 0 to find the interval where speed is increasing.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Position Function
The position function, denoted as s = f(t), describes the location of an object at any given time t. In this case, f(t) = 18t - 3t² represents a quadratic function where the position is influenced by both linear and quadratic terms. Understanding this function is crucial for analyzing the object's motion and determining its speed and acceleration.
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Relations and Functions
Velocity and Speed
Velocity is the rate of change of position with respect to time, calculated as the derivative of the position function, v(t) = f'(t). Speed, being the absolute value of velocity, indicates how fast the object is moving regardless of direction. To determine when speed is increasing, one must analyze the behavior of the velocity function over the specified interval.
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Derivatives Applied To Velocity
Acceleration
Acceleration is the rate of change of velocity with respect to time, represented as the derivative of the velocity function, a(t) = v'(t). When acceleration is positive, the speed of the object is increasing. Thus, to find the intervals where speed is increasing, one must identify where the acceleration function is greater than zero within the given time frame.
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Derivatives Applied To Acceleration
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