Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 29
Textbook Question
Find and simplify the derivative of the following functions.
y = (3t−1)(2t−2)-1
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1
Step 1: Identify the function y = (3t - 1)(2t - 2)^{-1} as a product of two functions, u(t) = 3t - 1 and v(t) = (2t - 2)^{-1}.
Step 2: Use the product rule for differentiation, which states that if y = u(t)v(t), then y' = u'(t)v(t) + u(t)v'(t).
Step 3: Differentiate u(t) = 3t - 1 to find u'(t). The derivative of 3t is 3, and the derivative of -1 is 0, so u'(t) = 3.
Step 4: Differentiate v(t) = (2t - 2)^{-1} using the chain rule. Rewrite v(t) as (2t - 2)^{-1} = (2t - 2)^{-1} = (2t - 2)^{-1}. The derivative of (2t - 2)^{-1} is -1(2t - 2)^{-2} times the derivative of (2t - 2), which is 2.
Step 5: Substitute u(t), u'(t), v(t), and v'(t) into the product rule formula to find y'. Simplify the expression to obtain the derivative of y.
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