Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Implicit Differentiation
Problem 3.8.33
Textbook Question
Use implicit differentiation to find dy/dx.
cos y2 + x = ey

1
Differentiate both sides of the equation cos(y^2) + x = e^y with respect to x, applying the chain rule where necessary.
For the left side, differentiate cos(y^2) using the chain rule: the derivative of cos(u) is -sin(u) * du/dx, where u = y^2.
For the right side, differentiate e^y with respect to x, using the chain rule: the derivative of e^y is e^y * dy/dx.
Set the derivatives from both sides equal to each other, remembering to include dy/dx terms from the implicit differentiation.
Solve the resulting equation for dy/dx to express it in terms of x and y.
Recommended similar problem, with video answer:

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
3mPlay a video:
Was this helpful?
Watch next
Master Finding The Implicit Derivative with a bite sized video explanation from Nick
Start learningRelated Videos
Related Practice