Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
5. Graphical Applications of Derivatives
Applied Optimization
Problem 4.5.71b
Textbook Question
Cylinder in a cone A right circular cylinder is placed inside a cone of radius R and height H so that the base of the cylinder lies on the base of the cone.
b. Find the dimensions of the cylinder with maximum lateral surface area (area of the curved surface).
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1
Define the variables: Let the radius of the cylinder be r and the height be h. The lateral surface area of the cylinder is given by the formula A = 2πrh.
Establish the relationship between the dimensions of the cone and the cylinder. Use similar triangles to express h in terms of r, R, and H. The relationship can be derived as h = H(1 - r/R).
Substitute the expression for h into the lateral surface area formula to express A solely in terms of r: A = 2πr(H(1 - r/R)).
Differentiate the area function A with respect to r to find the critical points: dA/dr = 2π(H(1 - r/R) - Hr/R).
Set the derivative dA/dr equal to zero to find the value of r that maximizes the lateral surface area, and then solve for r.
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