Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
2. Intro to Derivatives
Tangent Lines and Derivatives
3:34 minutes
Problem 3.40a
Textbook Question
Derivatives and tangent lines
a. For the following functions and values of a, find f′(a).
f(x) = √3x; a= 12
Verified step by step guidance
1
Step 1: Identify the function f(x) = \sqrt{3x}. This is a composition of functions, where the outer function is the square root and the inner function is 3x.
Step 2: To find the derivative f'(x), use the chain rule. The chain rule states that if you have a composite function f(g(x)), the derivative is f'(g(x)) * g'(x).
Step 3: Differentiate the outer function \sqrt{u} with respect to u, which is \frac{1}{2\sqrt{u}}. Here, u = 3x.
Step 4: Differentiate the inner function 3x with respect to x, which is 3.
Step 5: Apply the chain rule: f'(x) = \frac{1}{2\sqrt{3x}} * 3. Simplify this expression to find f'(x), and then evaluate it at a = 12 to find f'(12).
Recommended similar problem, with video answer:
Verified Solution
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
3mPlay a video:
Was this helpful?
Watch next
Master Slopes of Tangent Lines with a bite sized video explanation from Nick
Start learningRelated Videos
Related Practice