Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 53
Textbook Question
Suppose f'(x) < 2, for all x ≥ 2, and f(2) = 7. Show that f(4) < 11.
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1
Start by using the Mean Value Theorem, which states that if a function is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one c in (a, b) such that f'(c) = (f(b) - f(a)) / (b - a).
Set the interval as [2, 4] where a = 2 and b = 4. According to the Mean Value Theorem, there exists a c in (2, 4) such that f'(c) = (f(4) - f(2)) / (4 - 2).
Substituting the known value f(2) = 7 into the equation gives us f'(c) = (f(4) - 7) / 2.
Since we know that f'(x) < 2 for all x ≥ 2, we can substitute this into our equation: (f(4) - 7) / 2 < 2.
Multiply both sides of the inequality by 2 to eliminate the fraction, leading to f(4) - 7 < 4, and then solve for f(4) to conclude that f(4) < 11.
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